I believe you have to use power rules for these so for the numerator (x^5yz^4)^3 the power outside of the bracket will multiply with the powers inside the bracket in order to simplify this part so the numerator of the fraction would be x^15y^3z^12 (because 5x3=15, 1x3=3, 4x3=12)
Next simplify the fraction this is done by subtracting the powers so x^15y^3z^12/x^3yz =x^12y^2z^11 (because any singular letter term ie y can also be seen as y^1, using this 15-3=12, 3-1=2, 12-1=11) this is your final answer so a=12 b=2 and c=11
I believe the first one is h becuase there is a y on the left side.
for the second one just find the slope for the points and see which one doesn't fit in the groups (I would use tables)
and for the last one try writing equations for them.
but idk tho that's just what I would do.
there are many combinations for it, but we can settle for say
![\bf \begin{cases} f(x)=x+2\\[1em] g(x)=\cfrac{9}{x^2}\\[-0.5em] \hrulefill\\ (f\circ g)(x)\implies f(~~g(x)~~) \end{cases}\qquad \qquad f(~~g(x)~~)=[g(x)]+2 \\\\\\ f(~~g(x)~~)=\left[ \cfrac{9}{x^2} \right]+2\implies f(~~g(x)~~)=\cfrac{9}{x^2}+2](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20f%28x%29%3Dx%2B2%5C%5C%5B1em%5D%20g%28x%29%3D%5Ccfrac%7B9%7D%7Bx%5E2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%28f%5Ccirc%20g%29%28x%29%5Cimplies%20f%28~~g%28x%29~~%29%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%28~~g%28x%29~~%29%3D%5Bg%28x%29%5D%2B2%20%5C%5C%5C%5C%5C%5C%20f%28~~g%28x%29~~%29%3D%5Cleft%5B%20%5Ccfrac%7B9%7D%7Bx%5E2%7D%20%5Cright%5D%2B2%5Cimplies%20f%28~~g%28x%29~~%29%3D%5Ccfrac%7B9%7D%7Bx%5E2%7D%2B2)
To solve this question, we can use the tangent. The adjacent leg to the angle will have a length of 9.3 and the opposite leg will have a length of 7.4
Using these, we can create an equation to solve for unknown angle (let it be x) using the tangent.

Take the inverse tangent, or arc tangent, on both sides.


Your answer is the first choice. I hope this helps! :)