This can be solved by Newton's binomial formula
Tk+1 = (n k) a∧(n-k) b∧k k+1=7 => k=6, n=11 , a=-3x and b=-2y
T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6
T7= 462 (-3x)∧5 (-2y)∧6
The correct answer is A.
Good luck!!!
This answer is correct. The absolute value of a number is its distance from 0, and we are looking for an absolute value of 1. Both -1 and 1 are 1 whole number away from 0.
Answer:
answer is 2
Step-by-step explanation:
if you create an equation: (s+4)x2 = boris s-1x12 = opa
only one that only works out is 2
