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galben [10]
3 years ago
15

The pictogram shows what people ate when they went to a restaurant.

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0

Answer:

Step-by-step explanation: so you calculate how many people ate chicken, beef, fish or are vegetarian then you will add it all together

chicken=128

beef= 80

fish=32

vegetarian=112

128+80+32+112= 352 people ate at the restaurant

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Please help due soon!!!
butalik [34]

Hey there!


Question #1.
2^6 + (2^3)^3

= 64 + (8)^3

= 64 + 8^3

= 64 + 512

= 576


Therefore, the answer should be:

Option A. 576


Question #2.
11^-4 * 11^8

= 1/14,641 * 214,358,881

= 14,641

≈ 11^4

Therefore, the answer should be:

Option C. 11^4


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
2 years ago
Read 2 more answers
Find p(-4) and p(2) for the function p(x)=11x^5-11x^4-5x^2+15x-8
egoroff_w [7]

hi,

you must replace x by the number between parenthese.

I show you with the first one and let you do the second one

p(x) = 11x^5 -11x^4 - 5x^2 +15x-8

p(-4)  =   11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8

p(-4) =     11  ( -1024- 256) - 5*16 -60-8

p(-4) =   11 ( -1280) -80-60-8

p(-4)   =    - 14080 - 148

p(-4) =   - 14 228

7 0
2 years ago
Ling tried to solve an equation step by step.
Ipatiy [6.2K]

Step-by-step explanation:

<em>I</em><em> </em><em>didn't</em><em> </em><em>understand</em><em> </em><em>a thing</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
2 years ago
Read 2 more answers
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
2 years ago
What is the value of (-5)^4?
disa [49]

Answer:

-20

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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