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4 years ago

Rules for multiplying and dividing by 1 and 0

Mathematics

2 answers:

liubo4ka [24]4 years ago

7 0

Mutiplying: the product is always 0

natita [175]4 years ago

3 0

Multiplying anything by 1 is always the number your multiplying it by so for example 1*2=2

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WILL GIVE BRAINLIEST 80 POINTS ASAP!!

Drupady [299]

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2 years ago

Assume the resting heart rates for a sample of individuals are normally distributed with a mean of 75 and a standard deviation o

Shalnov [3]

Answer:

a) 0.975

b) 0.16

c) 0.475

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 75

Standard deviation = 5

We also have that since the normal distribution is symmetric, 50% of the measures are below the mean and 50% are above.

a. The relative frequency of rates less than 85 using the 68-95-99.7 rule is

85 is two standard deviations above the mean.

So all the 50% below the mean is below 85

And of the 50% above the mean, 95% is less than 85. So

0.5 + 0.95*0.5 = 0.975

b. The relative frequency of rates greater than 80 using the 68-95-99.7 rule is

80 is one standard deviations above the mean.

Of the 50% above the mean, 68% is less than 80. So 100-68 = 32% is more than 80.

0.32*0.5 = 0.16.

c. The relative frequency of rates between 65 and 75 using the 68-95-99.7 rule is

Within the mean and two standard deviations below the mean.

So 95% of 50%

0.95*0.5 = 0.475

6 0

4 years ago

11/2 z + 9/5 = 1.8 + 12z -6.5z=?

storchak [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

8 0

4 years ago

Select the correct answer. The supply and demand curves for a product line of bicycles are shown. Approximately where is the equ

Dmitry_Shevchenko [17]

Answer:

B. (132,220)

Step-by-step explanation:

The equilibrium point is the point where the quantity demanded is equal to the quantity supplied.

The equilibrium point (equilibrium price and equilibrium quantity) occur at the point where the supply and demand curves cross each other.

From the graph, we can see that the supply and demand curve cross each other at point. The equilibrium point is this point and it is gotten by tracing to the vertical and horizontal axis.

The equilibrium point is at (132, 220).

Hence the equilibrium price = $132 and equilibrium quantity = 220

6 0

3 years ago