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viva [34]
4 years ago
9

A student is given a quadratic equation in vertex form. He determines the vertex and axis of symmetry, and then sketches the par

abola so that it is symmetrical about the axis of symmetry. Is this sufficient? Explain.
Mathematics
1 answer:
igor_vitrenko [27]4 years ago
5 0

Answer:

The information with which the parabola is constructed is insufficient

Step-by-step explanation:

The vertex form of a quadratic equation is given as follows;

f(x) = a(x - h)² + k

The steps to draw the graph of a quadratic function given in vertex form, we are required to do the following;

1) Definition of the variables, (a, h and k) of the quadratic equation (given in vertex form)

The vertex of the quadratic equation in vertex form is (h, k)

2) Given that the vertex point is given, the vertex point is then plotted on the graph

3) Draw the parabola axis of symmetry that passes through the vertex point

4) Determine the direction to which the parabola opens from the sign of the variable a as follows;

i) When a is positive, the parabola opens upwards

ii) When a is negative, the parabola opens downwards

5) Determine if the parabola has x-intercepts and plot them

A parabola has x intercepts when;

i) The parabola opens downwards, that is, the variable, a, is negative and also the vertex (h, k) is above the x-axis or k is positive

ii) The parabola opens upwards, that is, the variable, a, is positive and also the vertex (h, k) is below the x-axis or k is negative

6)  Determine y-intercepts and plot them as follows;

At the y-intercept, x = 0, therefore;

f(x) = a(x - h)² + k

f(0) = a(0 - h)² + k = a·h² + k

6) If any additional points are required, they should plotted and then the graph of the function is then drawn making sure to be symmetrical about the vertex and to pass through all the plotted points.

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Answer:

Multiply the number of cubic feet by 1728 to get the answer.

10*1728=x

x=17280

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What is 1 & 5/7 times 2 & 3/4
VARVARA [1.3K]

The solution of 1\frac{5}{7} \times 2\frac{3}{4} is \frac{33}{7} \text{ or } 4.714

<em><u>Solution:</u></em>

Given that we have to find the solution of given expression

Given expression is:

1\frac{5}{7} \times 2\frac{3}{4}

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

Therefore,

1\frac{5}{7} = \frac{1 \times 7+5}{5} = \frac{12}{5}

2\frac{3}{4} = \frac{2 \times 4+3}{4}=\frac{11}{4}

Now the expression becomes,

1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4}

Solve and simplify the above expression

1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4} = \frac{33}{7}\\\\1\frac{5}{7} \times 2\frac{3}{4} = \frac{33}{7}

In decimal form we get,

\frac{33}{7}=4.714

Thus the solution to given expression is found

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4 years ago
Kate scored 85,78,72, and 81 on 4 math tests. What score does she need on the fifth test to have at least an 80 average?
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I am not good in this kind of question so maybe 84?

suppose the full marks for each of them is 100 so for 5 of them it will be 500 cause if you if you multiply 100 full marks by 5 it will be 500

so the answer to this question is maybe 84?

cause if you add all of them with 84 the outcome will be 400 and if you divide the 400 by 5 it will be 80

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3 years ago
A 25-foot ladder is placed 7 feet from the wall, as shown.
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The answer is 8 feet.

Step-by-step explanation:

Let x = height where the ladder hits the building

7 squared+x squared=25 squared

49+x squared=625

x squared=576

x=24 feet

Let x = distance from wall:

x^2 + 20^2 = 25^2

x^2 + 400 = 625

x^2 = 225

x = 15 feet

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3 years ago
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