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3 years ago

What is the equation for a line that passes through the points (3,1) and (4,-1)

Mathematics

1 answer:

lbvjy [14]3 years ago

6 0

Answer:

y-y/x-x

1--1/3-4

1+1/3-4

2/-1

= -2

then you plug in with any one of the points

y=mx+b

1= -2(3) + b

1 = -6 + b

b = 1+6

b = 7

so the equation is: y = -2x+7

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What is X+y(2x-3)=18

stiks02 [169]

What is X and Y ..
y=?
X=?

7 0

3 years ago

Hi what isthe answer

REY [17]

Answer:

2x^7

Step-by-step explanation:

2x^4 × x^3 =

= 2x^(4+3)

= 2x^7

8 0

3 years ago

Pens are sold in packs of 3 for $5. Pencils are sold in packs of 4 for $1. Mr. James bought 9 pens and 4 pencils and also spent

Brums [2.3K]

Answer:

C.(3 × $5) + $1 + $3 = x

Step-by-step explanation:

3x9=15($15 for pens)

$1 for pencils

$3 (for paper)

so (3 × $5) + $1 + $3 = x

hope this helps! C:

7 0

3 years ago

In a test (+4) marks are given for every correct answers and (-3) marks are given for every incorrect answers 1) Tahiya answered

stealth61 [152]

Answer:

Tahiya attempted 3 incorrect answers.

Helmin attempted 11 incorrect answers.

Step-by-step explanation:

Correct = +4

Incorrect = -3

1) Tahiya got 12 correct answers and scored a 40, the number of incorrect answers was:

$4*12-3I=40\\I=\frac{8}{3}\\I=2.67$

2) Helmin got 5 correct answers and scored a -14, the number of incorrect answers was:

$4*5-3I=-14\\I=\frac{34}{3}\\I=11.33$

In both cases the number of incorrect answers obtained is a fraction, which means that either the data provided is inaccurate, or that the scores obtained by the students are approximate. Let's round the number of incorrect answers to the nearest whole answer.

Tahiya attempted 3 incorrect answers.

Helmin attempted 11 incorrect answers.

4 0

3 years ago

Please help! The radius of a sphere is claimed to be 3.0 inches, correct to within 0.01 inch. Use linear approximation to estima

Vilka [71]

Answer:

0,36π inches³ or simply 1.13 inches³

Step-by-step explanation:

In this case, first, we need to calculate the volume of the sphere with the formula:

V = 4πr³/3

Replacing the data we have:

V = 4π(3)³/3

V = 36 in³

Now that we have the volume we need to calculate the resulting error. In this case, using linear approximation we have to use the derivates of V and r, so we have the following:

If V = 4πr³/3

Then the derivate of V (dV) would be:

dV = 4π*3*r²/3 dr

Where dr is the error of radius so:

dV = 4π*r² dr

Solving for dV:

dV = 4*3.14*(3)²*(0.01)

dV = 1.13 in³

So at the end, we just report the volume of the sphere as

V = 36 ± 1 in³

dV =

3 0

3 years ago