Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
Answer: (-24,2)
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Work Shown:
The y coordinate stays the same. Only the x coordinate will change.
(1/4)*x = -6
x = -6*4
x = -24 is the new x coordinate
Plugging x = -24 into f((1/4)x) leads to f(-6) = 2
Since y=x+3 (given)
Put value of y in equation x+y=(-3)
x+x+3=(-3)
2x=(-6)
x=(-3)
Put x=(-3) in x+y=(-3)
(-3)+y=(-3)
y=0
So, x=(-3)
y=0
Answer:
8x+140=180
8x=40
x=5°
Step-by-step explanation:
Sum of angles in a straight line=180°
