Answer:
Depth of the rain gutter is 8 inches
Step-by-step explanation:
Let’s assume ‘x’ is the depth of the rain gutter
Then the width of the rain gutter can be written as 16 - 2x
Cross sectional area
A = depth x width
Substitute values
A = x*(16 - 2x)
A = 16x – 2x^2
Now according to axis of symmetry for maximum area x = -b/2a
x = -16/2*(-2)
x = 4 inches depth of rain gutter, substitute the value of x to get
Width of rain gutter 16 – 2(4) = 8 inches
Area of the rain gutter for maximum water flow
A = 4 * 8
A = 32 square inch.
Answer: The mechanic worked for 4.25 hours for the fourth customer.
First find out the slope.
Y^2-y^1/x^2-x^1
210-90/3-1=60
Slope: 60
Then find out what the y-intercept is by plugging in values we know into y=mx+b
90=60(1)+b
30=b
Y=60x+30
Substitute the y with 285 to find out the x (hours)
285=60x+30
4.25=x
To be tripled means to be multiplied by 3. So multiply 2 3/4 by 3
2 3/4*3=8 1/4
Therefore the amount of milk needed is 8 1/4 cup
The answer is a the first one
