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3 years ago

What is the solution to –4(8 – 3x) ≥ 6x – 8? x ≥ – x ≤ – x ≥ 4 x ≤ 4

Mathematics

2 answers:

ollegr [7]3 years ago

7 0

Answer:

x ≥ 4

Step-by-step explanation:

–4(8 – 3x) ≥ 6x – 8

Distribute

-32 +12x ≥ 6x – 8

Subtract 6x from each side

-32 +12x-6x ≥ 6x-6x – 8

-32 +6x ≥ – 8

Add 32 to each side

-32 +32 +6x≥ 32– 8

6x ≥ 24

Divide by 6

6x/6 ≥ 24/6

x ≥ 4

lesya [120]3 years ago

4 0

Answer:

c. x ≥ 4

Step-by-step explanation: just took the test

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galina1969 [7]

Answer:

8h+100

8.50h+80

Step-by-step explanation:

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2 years ago

The side lengths, in centimeters, of a triangle are 5x, 32, and 2(3x + 2). perimeter of the triangle is 80 centimeters. what is

Lerok [7]

Answer:

20 cm

Step-by-step explanation:

5x + 32 + 6x + 4 = 80

11x + 36 = 80

11x = 44

x = 4

sides of triangle:

5(4) = 20 cm

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2 years ago

What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

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3 years ago

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Oliga [24]

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