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Snowcat [4.5K]
3 years ago
15

at 4:00 p.m. karl stands next to his house and measures his shadow and the houses shadow. karl’s shadows is 8 ft. long. the hous

es shadow is 48 ft. long. if karl is 6 ft. y’all, how tall is his house?
Mathematics
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

36 feet

Step-by-step explanation:

You have to figure out the relation for 6 (karl's real height) and 8 (his shadow's length) by dividing 6 by 8, which gets you a 3/4 ratio of shadow to real height. Since we have the house's height, 48/4=12. Multiplying that by 3 gets you 36, therefore his house is 36 feet.

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Answer:

  (a)  169.1 m

Step-by-step explanation:

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  169.1 m

__

The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

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