Answer:
Yes
Step-by-step explanation:
Answer:
roots=(5±sqrt(33))/4
Step-by-step explanation:
roots=(-b±sqrt(b^2-4ac))/2a
roots=(-(-5)±sqrt(25+8))/(2*2)
roots=(5±sqrt(33))/4
roots=(5+sqrt(33))/4 and (5-sqrt(33))/4
Answer:
mhhm yea this is very questioned questioned
Step-by-step explanation:
yea mhm
Answer: 3∛2
<u>Step-by-step explanation:</u>
First, factor 128 .... you need three common factors to bring one on the outside of the radical.
![\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B128%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%5Ccdot%202%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Ccdot%204%5Csqrt%5B3%5D%7B2%7D%20%5C%5C%5C%5C%5C%5C%3D%5Clarge%5Cboxed%7B3%5Csqrt%5B3%5D%7B2%7D%20%7D)