Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,

Taking last two ratio,

Putting the value of BC , AC ,∠A,∠B


≈734.106 miles
Therefore they are 734.106 miles apart.
Answer:
A.) (7t³ + 2k^4)(7t³ - 2k^4)
Step-by-step explanation:
Factor the following:
49 t^6 - 4 k^8
49 t^6 - 4 k^8 = (7 t^3)^2 - (2 k^4)^2:
(7 t^3)^2 - (2 k^4)^2
Factor the difference of two squares. (7 t^3)^2 - (2 k^4)^2 = (7 t^3 - 2 k^4) (7 t^3 + 2 k^4):
Answer: (7 t^3 - 2 k^4) (7 t^3 + 2 k^4)
Answer:
222 ft/sec
Step-by-step explanation:
Essentially you're being asked to find the unit speed (that is, distance per sec).
1000 ft
------------ = 222 feet/sec is the approx. average speed / unit speed
4.5 sec