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Marianna [84]
1 year ago
5

P and q are two arithmetic sequences. The first four terms of sequence P are 2,6,10,14. The nth term of sequence Q is 145-3n. Th

e rth term of sequence P has the same values as the rth term of sequence Q. Work out the value of r.
Mathematics
1 answer:
Tomtit [17]1 year ago
5 0

Answer:

r = 21

Step-by-step explanation:

nth of sequence P :

T_{n} = 4n -2

r^{th} term : 4r-2=145-3r\\4r+3r=145+2\\7r=147\\r=21

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Solve the equation 4t =6t-8/5
adoni [48]

Answer:

3.2

Step-by-step explanation:

0 = 2t - 8/5

8/5 = 2t

16/5 = t

3.2 = t

5 0
3 years ago
A candy company uses 8 gallons of corn syrup to make 1,776 pieces of candy. If they use 52 gallons of corn syrup per hour, how m
kondor19780726 [428]

Answer: 11,544 pieces of candy are made per hour.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Gallons of corn syrup used: 8 </em>
  • <em>Pieces of candy produced: 1,776 </em>
  • <em>gallons of corn syrup per hour: 52 </em>

If we apply proportions:

8 /1,776 = 52/x

Where x is the pieces of candy made per hour.

Solving

x = 52x1, 776 /8

x = 11,544

11,544 pieces of candy are made per hour.

4 0
3 years ago
In STU, SU =18 and TU =13. Find m
erastova [34]

Answer:

m=22.2

Step-by-step explanation:

By using the Pythagorean’s theorem i.e

hypotenuse^2=opposite^2+adjacent^2

Where

Hypotenuse =unknown

Opposite =18

Adjacent =13

Hyp^2=18^2+13^2

Hyp^2=324+169

Hyp^2=493

Hyp=sqrt 493

Hyp=m=22.2

3 0
3 years ago
Taylor and Jesse are buying a magazine for $3.75 and a snack for $2.49 what is s the total cost of the two items?
Kazeer [188]

Hey There!

The answer you are looking for is; $6.24!

Work:

You simply add $3.75 + $2.49 together.

Since .75 + .29 = 1.24, you carry the one over to the full dollar.

3 + 2 + 1 = 6.

= 6.24

Hope I helped! 5 stars and brainliest are always appreciated.

7 0
3 years ago
Read 2 more answers
Write the ratio as a fraction in lowest terms. Be sure to make necessary conversions:
agasfer [191]

Answer:12533

Step-by-step explanation:

4 0
2 years ago
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