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S_A_V [24]
2 years ago
7

Consider the function represented by 9x + 3y = 12 with x as the independent variable. How can this function be written using

Mathematics
2 answers:
ss7ja [257]2 years ago
7 0

Answer:

y=-3x+4

Step-by-step explanation:

In function notation we have y in one side and the x (like free variable) and other numbers in the other side.

9x+3y=12

3y=12-9x

3y=-9x+12

y=(-9x+12)/3

y=-3x+4

Illusion [34]2 years ago
6 0

Answer:

the function is : f(x) = -3x+4

Step-by-step explanation:

hello :

9x + 3y = 12   calculate y :     3y = -9x+12

divid by : 3        y = -3x+4

the function is : f(x) = -3x+4

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What is the AREA of this figure?
elena-14-01-66 [18.8K]

Answer:

532m squared is the answer

Step-by-step explanation:

Split the shape into two shapes

one will be a square and the other one a triangle

1) since the length and the width of the square is 18m just Multiply

18x18=324m squared

2) look carefully the width of the square you split is equal to the base of the triangle, so you connect the 18 and the 8 together.

18+8=26m squared

3) Now solve the triangle since you know the height which is 16m squared.

A=lw/2

26x16=416

416 divided by 2 is 208

4) finally just Add

208+324=532m squared

Hopes this helps!

7 0
3 years ago
-73 greater than or equal to 15 + 11x
Alecsey [184]
-73 ≥ 15 + 11x 
so the first thing you should do is to add -15 on both sides of the equation so you will have:
-73 -15 ≥ 11x 
- 88 ≥ 11x 
so the answer is:
-88/11 ≥ x or -8 ≥ x :)))
i hope this is helpful
have a nice day 
5 0
3 years ago
Read 2 more answers
Find the 10th term of the sequence 1,10,19,28,...
Rainbow [258]
For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82

For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4
5 0
3 years ago
Use long or synthetic division to find the following quotients <br>(x^3+2x^2!22x-45)÷(x+5) ​
svetoff [14.1K]

Answer:

\boxed{\textsf{ The quotient is $\sf x^2-3x-7$ and the remainder is (-10).}}

Step-by-step explanation:

Here we will be using long division method to find the quotient . Here we need to divide (x³+2x²-22x-45) and (x+5) . So lets divide .

x+5) x³+2x²-22x-45 ( x² -3x -7

x³ + 5x²

- -

______________

- 3x²-22x -45

-3x² -15x

+ +

______________

-7x -45

-7x -35

______________

-10

<u>Quotient</u><u> </u>= x² -3x -7

<u>Remainder </u>= (-10)

<h3><u>★</u><u>Hence </u><u>the</u><u> </u><u>quotient</u><u> </u><u>is </u><u>x²</u><u> </u><u>-3x </u><u>-</u><u>7</u><u> </u><u>and </u><u>the</u><u> </u><u>remainder</u><u> </u><u>is </u><u>(</u><u>-</u><u>1</u><u>0</u><u>)</u><u> </u><u>.</u></h3>
7 0
3 years ago
Ms. Ironperson and Mr. Thoro are making Avenger posters to give children when they visit Avenger Academy. Ms. Ironperson has com
nekit [7.7K]

Answer:

1) When this does happen, how many posters will each Avenger have completed?

24 posters each.

2) If x denotes the number of days and y denotes the number of posters, what are the equations needed to solve this problem?

y = 12 + 6x.......... Equation 1

y = 12x .......... Equation 2

Step-by-step explanation:

1) When this does happen, how many posters will each Avenger have completed?

We are told in the question:

Number of days = x

Number of posters = y

Ms. Ironperson has completed 12 posters and will complete 6 more per day.

y = 12 + 6x.......... Equation 1

Mr. Thoro has not started yet but can make 12 per day.

y = 12x................Equation 2

Hence, the equations needed to solve this problem:

y = 12 + 6x.......... Equation 1

y = 12x .......... Equation 2

We substitute 12x for y in equation 1

y = 12 + 6x.......... Equation 1

12x = 12 + 6x

Collect like terms

12x - 6x = 12

6x = 12

x = 12/6

x = 2

Hence, since x = the number of days,

The number of days = 2 days

Substitute 2 for x in Equation 2

y = 12x .......... Equation 2

y = 12 × 2

y = 24 posters.

Since y = number of posters,

number of posters = 24 posters.

We were told in the question that, when Mr Thoro catches up with Ms Ironperson, that would both have completed the same number of posters.

Hence, both Avengers would have completed 12 posters each.

7 0
3 years ago
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