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3 years ago

A rectangular athletic field is twice long as it is wide the perimeter is 90 yard dismention?

Mathematics

1 answer:

Shkiper50 [21]3 years ago

5 0

Ah well this would look like 2(30) + 30 = 90 aka 2L + W = 90

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A blueberry muffin is on sale for 5% off. It's sale price is $1.90. What was the original price?

Tatiana [17]

Answer:

The original price was $2.

Step-by-step explanation:

The muffin is on sale for 5% off. This means it is being sold for 95% of its original price.

Its sale price is $1.90. This means that 95% of its original price is 1.90.

Let's set up an equation.

95% of original price is $1.90.

0.95 • x = 1.90

Divide both sides by 0.95 to isolate x.

x = 2

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Hope this helps!

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3 years ago

Read 2 more answers

What is the slope? Show work as well please.

stealth61 [152]

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3 years ago

Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length

nataly862011 [7]

We have been given that Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length. Wally is 68 inches tall, casts a shadow that is 41 inches in length.

We will use proportions to solve for the height of the statue because proportions state that ratio between two proportional quantities is same.

$\frac{\text{Height of statue}}{\text{Shadow of statue}}=\frac{\text{Height of Wally}}{\text{Shadow of Wally}}$

Upon substituting our given values in above equation, we will get:

$\frac{\text{Height of statue}}{\text{164 cm}}=\frac{\text{68 inch}}{\text{41 inch}}$

$\frac{\text{Height of statue}}{\text{164 cm}}\times \text{164 cm}=\frac{\text{68 inch}}{\text{41 inch}}\times \text{164 cm}$

$\text{Height of statue}=\frac{\text{68 inch}}{1}\times 4$

$\text{Height of statue}=272\text{ inches}$

Therefore, the height of the statue is 272 inches.

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3 years ago

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yarga [219]

Answer:

B. $\frac{1}{5}$

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2 years ago

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Salsk061 [2.6K]

C is the correct answer. An equilateral triangle is a type of triangle.

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