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MaRussiya [10]
3 years ago
8

When constructing parallel lines, how can you be sure the lines you constructed are parallel?

Mathematics
2 answers:
Vesnalui [34]3 years ago
5 0

Answer:

Using a ruler or a distance measure item and make sure the distance between them is always the same. At least in 2 points, it must be.

Step-by-step explanation:

Parallel lines are by definition the ones that never touch each other. So are two lines "pointing" in the same direction and the space between the two lines never change.

In order to confirm the best method is to compare at least 2 measure of the space between the lines and must be the same. This must done with the highest accuracy.

Reika [66]3 years ago
3 0
The distance between the two lines is consistent when checked with a compass. 


Please Rate Brainliest!!!! It would mean alot
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Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.

First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
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Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.

Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).

Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.

Option D: </span><span>1 2 πr2h
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Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>
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