Question

NEED HELP ASAP 70 POINTS

Answer 1

Answer:

Step-by-step explanation:

Statement                                                                Reason

ΔACE, BD║AE                                                          Given

∠4≅∠1 and ∠3≅∠2                                      Corresponding angle postulate

ΔACE is similar to ΔBCD                             Angle-Angle similarity postulate

$\frac{CA}{CB}=\frac{CE}{CD}$          Definition of similar triangles

CA=CB+BA and CE=CD+DE                        Segment addition postulate

$\frac{CB+BA}{CB}=\frac{CD+DE}{CD}$ Substitution property of equality.

$\frac{CB}{CB}+\frac{BA}{CB}=\frac{CD}{CD}+\frac{DE}{CD}$ Addition of fractions.

$1+\frac{BA}{CB}=1+\frac{DE}{CD}$    Simplification of fractions

$\frac{BA}{CB}=\frac{DE}{CD}$         Subtraction property of equality.

Answer 2

Ayo, for anyone who needs it -