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Leto [7]
3 years ago
6

Abby owns a comic book that originally sold for 12¢ in 1969. In 2014, the comic book had an appraised valued of $3,700. Given th

at the annual percentage rate has been constant, what is the annual percentage rate of growth?
A) 23.28% B) 25.82% C) 26.33% D) 28.94%
Mathematics
1 answer:
Trava [24]3 years ago
3 0

Hi,

Answer: B) 25.82%

<u>My work:</u> For this problem you can easily achieve this problem (Preferably with a caculator) by taking the date’s 2014 and 1969 the time of growth and subtract them. When you do this you get the answer 45. From there you you take 45 (With caculator) and multiply it with 25.82 % (To do this you take 25.82 and press 2nd, then the percent). When you do this you get 11.619 which rounded is 12; furthermore, which is your answer.

I Hope I Helped!

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The volume of a pyramid with a square base, where the perimeter of the base is 7.3\text{ ft}7.3 ft and the height of the pyramid
Dennis_Churaev [7]

Answer:

12.21ft³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, square based pyramid.

Volume of square based pyramid is expressed as

V= a²(h/3)

Given data

Perimeter p = 7.3ft

Height h= 11.1ft

Since the shape has a square base let us solve for the length of each side

Perimeter of square p = a+a+a+a

p= 4a

7.3= 4a

a= 7.3/4

a= 1.83ft

Substituting our given data we have

Volume = 1.83²(11.1/3)

V= 3.3*3.7

V= 12.21ft³

8 0
3 years ago
How can you decompose the composite figure to determine its area
Nataly_w [17]

Answer:

4 as a trapezoid, a rectangle, and two squares

Step-by-step explanation:

The diagram below is a composite figure .To determine it area the composite figure can be decomposed into various shapes.

The shapes it can be decomposed are a trapezoid , a rectangle and 2 squares.

The top side of the composite figure forms a trapezoid . A trapezoid is a quadrilateral with one pair of parallel sides. It is also known as trapezium.

The shape below the trapezoid can be cut into a rectangle .A rectangle is a quadrilateral with opposite sides equal in length and are also parallel.

The two shapes formed below the rectangle are squares. Squares are quadrilaterals with all sides equal in length and opposite sides are parallel.  

4 0
3 years ago
In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C', A', and B'
Daniel [21]

Original coordinates of the points:

A (8,15) ; B (12,13) ; C (8,10)

Dilated scale factor of 3.

A ⇒ 3x = 3(8) = 24 ; 3y = 3(15) = 45 ⇒ A' (24,45)

B ⇒ 3x = 3(12) = 36 ; 3y = 3(13) = 39 ⇒ B' (36, 39)

C ⇒ 3x = 3(8) = 24 ; 3y = 3(10) = 30 ⇒ C' (24, 30)

The given image forms a right triangle. So, I'll get the short leg and long leg of the right triangle to solve for the hypotenuse, length of CB.

Short leg: y value of B and C

  • 39 - 30 = 9

Long leg: x value of B and C

  • 36 - 24 = 12

a² + b² = c²

9² + 12² = c²

81 + 144 = c²

225 = c²

√225 = √c²

15 = c

The length of CB is 15 units. (option B).

4 0
2 years ago
Answer the questions attached:
arlik [135]

1. I'm not completely sure, but these angles seem to be complementary, meaning they add up to 90°. Since 75° + x = 90°, x = 15°.

2. These lines seem to be parallel. ∠4 ≅ ∠1 because they are vertical angles, ∠5 ≅ ∠1 because they are corresponding angles, and because ∠8 ≅ ∠4 (corresponding angles), ∠8 ≅ ∠1 as well. The final answer is ∠4, ∠5, and ∠8. Hope this helps!

5 0
4 years ago
Read 2 more answers
Solve the formula for m.<br> e = MC^2<br> M=
azamat

Answer:

M  = \frac{e}{C^2 }

Step-by-step explanation:

e=MC^2  \\  \frac{e}{C^2 }  = M \\ \huge \red{ \boxed{M  = \frac{e}{C^2 } }}

8 0
3 years ago
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