(b-c)/c can be separated into b/c-c/c, which is the same as b/c - 1. so a= b/c -1 add one to both sides of equations a+1 = b/c -1+1 1 cancels out on the right side leaving a+1 = b/c multiply both sides by c c ×(a+1)= (b/c)×c c cancels out on the right side making c×(a+1) = b divide both sides by a+1 c =b/(a+1)
