Answer:
No
Step-by-step explanation:
Let's check the first statement with an example. 2 and 3 are positive numbers and their sum (5) is also positive so his first statement is true.
To check the second statement let's look at the negative numbers -1 and -8 for example. Their sum (-9) is also negative so his second statement is true.
To check the third statement let's look at the numbers 9 and -5. One is positive and one is negative, but their sum (4) is positive, so his third statement is false. However if we look at the numbers 4 and -7, their sum is negative so the third statement is partially false.
There's a lot of different approaches to this question, but the easiest one I see is this:
If a chord goes through the center of the circle, it is a diameter. That's 180 degrees we don't have to worry about. 47 is an inscribed angle, so we can multiply it by two to get 94 degrees. Subtract 94 from 180 to get 86.
See y? It's also an inscribed angle. To get it, we just take the 86 we just found for the remaining arc and divide by two.
The measure of y is 43.
There were exactly 31 people in chess club in 2002
Answer:
![P= \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]](https://tex.z-dn.net/?f=P%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.5%260.25%260.25%5C%5C0.25%260.5%260.25%5C%5C0.25%260.25%260.5%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
let a, b and c be the type of foods used in trail.
Example matrix combination for (1,1) is (a,a) is 0.5. Another Example for (1,2) is (a,b) is 0.25.
The diagonals are (a,a), (b,b) and (c,c) which means same food in two trails and its probability is 0.5. the rest would be 0.25
Therefore, stochastic matrix would have 3 by 3 matrix such as (a,a), (a,b) .... (c,c)
![\left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right] \\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.5%260.25%260.25%5C%5C0.25%260.5%260.25%5C%5C0.25%260.25%260.5%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
Answer:
20 students should be on each float
Step-by-step explanation:
Number of seniors = 100
Number of juniors = 80
To find number of students that should be on each float, find highest common factor (H.C.F) of 100 and 80
Write prime factorisation of 100 and 80.
100 = 
× 
80 = 
× 5
So,
H.C.F(100, 80) = × 5 = 4 × 5 = 20
Therefore,
20 students should be on each float
