Answer:
Pr(all will survive in one year) = 0.35 to 2 decimal places
Pr(at least 8 will survive) = 0.39 to 2 decimal places.
Step-by-step explanation:
Probability of a tree surviving one year is 0.9. While not surviving probability is 1 - 0.9 = 0.1
This is obtained from the 90℅ surviving rate for one year planted by the landscaping firm.
Probability that if 10 trees are planted, all will survive for one year is:
0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9 = 0.9^10 = 0.349
Probability that at least 8 will survive in one year can be expressed as
8 survived x 2 not survived +(or) 9 survived x 1 not survived +(or) 10 survived
= [(0.9^8)x(0.1^2) + (0.9^9)x(0.1^1) + (0.9^10)] = 0.391
B. Quadrant 3
The top left corner is quadrant 1 then the top right corner is quadrant 2 then the bottom right corner is quad 3
Step-by-step explanation:
i think u had done something wrong in equation
Well, there are 3 feet in a yard. So, 3ft=1yrd. Multiply the length value by 3. You could also multiply 3 by the # of yards (or in this situation, 8) Is that good enough?
Answer:
idk
Step-by-step explanation:
