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vaieri [72.5K]
3 years ago
12

An open topped box is constructed as follows: A 24 in. x 24 in. square bottom has four identical squares cut off at each corner.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Given

square bottom area is 24\times 24\ in.^2

Suppose x in. is cut from each corner to make a open box with maximum volume

New base area is (24-x)\times (24-x) in.^2

Volume of box

V=(24-x)^2\times x

Differentiate V w.r.t x to get maximum volume

\frac{\mathrm{d} V}{\mathrm{d} x}=2\cdot (24-x)(-1)+1\cdot (24-x)^2

Put \frac{\mathrm{d} V}{\mathrm{d} x}=0

\left ( 24-x\right )\left [ -2x+24-x\right ]=0

\left ( 24-x\right )\left [ 24-3x\right ]=0

x=24,8

but x=24 is not possible therefore x=8 will yield maximum volume

V=(24-8)^2\cdot 8=2048\ in.^2    

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Substituting the values we have:

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The statements that describe the given inequality are as follows:

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