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ZanzabumX [31]
4 years ago
12

I need major help.......................

Mathematics
1 answer:
irakobra [83]4 years ago
7 0

Answer:

0.108

Step-by-step explanation:

0.66 × 0.33 × 0.5 = 0.108.

Formula: L × W × H × 1/6.

L = 4

W = 2

H = 3

4×2×3.

We then have you multiply that by 1/6.

4×1/6 = 0.66.

2×1/6 = 0.33

3×1/6 = 0.5

0.66 × 0.33 × 0.5 = 0.108.

Now, onto the correct answers.

7) (4×1/6cm) × (2×1/6cm) × (3×1/6cm)

7 is correct, because the answer is diving each number by 1/6, and multiplying them with each other.

1) 1/216 × 24

1 is correct, because the answer when the question is evaluated is around 0.108. 1/216 × 24 = 0.11111111111. It is very close to the answer. This, indeed is correct.

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Which of these is an exponential parent function?
kipiarov [429]

Complete question is;

Which of these is an exponential parent function?

A. f(x) = x

B. f(x) = 2^(x)

C. f(x) = x²

D. f(x) = |x|

Answer:

B. f(x) = 2^(x)

Step-by-step explanation:

> In option A, f(x) = x

This function depicts a straight line with intercept as 0 and slope as 1.

> In option C, f(x) = x²

This function depicts a parabola open up since the leading coefficient is greater than 0.

> In option D: f(x) = |x|

This function depicts a straight line y = x for x > 0 and y = -x for x < 0

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5 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

F = \dfrac{9}{6^x}

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

W = \int\limits^{x_2}_{x_1} {F(x)} \, dx

with x_1 and x_2 the initial and final displacements respectively.

From the question, x_1  =0 and x_2 = 12.

Then

W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx

Evaluating the indefinite integral,

\int\limits \dfrac{9}{6^x} \, dx  =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx

From the rules of integration,

\int\limits a^x\, dx = \dfrac{a^x}{\ln a}

9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x

Returning the limits,

\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}

4 0
3 years ago
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