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ZanzabumX [31]
3 years ago
12

I need major help.......................

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

0.108

Step-by-step explanation:

0.66 × 0.33 × 0.5 = 0.108.

Formula: L × W × H × 1/6.

L = 4

W = 2

H = 3

4×2×3.

We then have you multiply that by 1/6.

4×1/6 = 0.66.

2×1/6 = 0.33

3×1/6 = 0.5

0.66 × 0.33 × 0.5 = 0.108.

Now, onto the correct answers.

7) (4×1/6cm) × (2×1/6cm) × (3×1/6cm)

7 is correct, because the answer is diving each number by 1/6, and multiplying them with each other.

1) 1/216 × 24

1 is correct, because the answer when the question is evaluated is around 0.108. 1/216 × 24 = 0.11111111111. It is very close to the answer. This, indeed is correct.

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5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
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Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
What is the least common multiple of 9 and 8
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Answer:

72 is the least common multiple

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