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3 years ago

Help plzzzzzzzzzzzzzzzzz

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

Answer: C

Step-by-step explanation:

on edu.

bixtya [17]3 years ago

5 0

Answer:

3 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units

Step-by-step explanation:

we know that

The isosceles trapezoid has :

Two parallel sides not equal in length called its bases (KL and NM)

Two non-parallel sides equal in length (LM and NK)

$NK=\sqrt{5}\ units$

The perimeter is equal to

$P=KL+LM+NM+NK$

substitute the values

$P=2\sqrt{2}+\sqrt{5}+\sqrt{2}+\sqrt{5}$

$P=(3\sqrt{2}+2\sqrt{5})\ units$

3 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units

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What is the common ratio for the sequence 1, 4, 16, 64,...? 2 4

PIT_PIT [208]

The given equation is a geometric sequence.
It has a common ratio. You can get it by dividing the number in the sequence by the number before it.

Just like r= 16/4= 4

4 0

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A microwaveable cup-of-soup package needs to be constructed in the shape of cylinder to hold 700 cubic centimeters of soup. The

Korvikt [17]

Answer:

r = 3.43 cm

h=18.94 cm

Step-by-step explanation:

The volume of the cylinder is:

$V=\pi r^{2}h=700cm^{3}$

where r is the radius of the circular base and h is the height of the cylinder.

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$(0.02)2\pi rh$

The cost ot the bottom of the container is:

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The cost ot the top of the container is:

$(0.09)\pi r^{2}$

Then, the total cost of the container is:

$C=(0.02)2\pi rh+(0.02)\pi r^{2}+(0.09)\pi r^{2} \\C=\pi r(0.04h+0.02r+0.09r)\\C=\pi r(0.04h+0.11r)$

From the volume, you could solve for one variable and substituting in the cost equation:

$h=\frac{700}{\pi r^{2}}\\C=\pi r(0.04(\frac{700}{\pi r^{2}})+0.11r)$

In order to minimize this fuction you need to calculate the derivative respect to r:

$\frac{dC}{dr} =\frac{dC}{dr}[\frac{28}{r}+0.11\pi r^{2}]\\\frac{dC}{dr} =-\frac{28}{r^{2} }+0.22\pi r$

The critical points of the function are obtained when dC/dr=0:

$-\frac{28}{r^{2}}+0.22\pi r=0\\0.22\pi r=\frac{28}{r^{2} }\\r^{3}= \frac{28}{0.22\pi } \\r=3.43 cm$

To evaluate if this critical point is a minimum, you should get the second derivative:

$\frac{d^{2} C}{dr^{2} } =\frac{28}{r^{3} }+0.22\pi \\$

For the critical point r = 3.43 cm, the second derivative is positive, which means that the critical point is a minimum.

Then, the dimensions for the package tht will minimize product cost are:

r = 3.43 cm

$h=\frac{700}{\pi r^{2} } =18.94cm$

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Yuliya22 [10]

Answer:

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