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2 years ago

Mx+nx=p solve for x please

Mathematics

1 answer:

Irina-Kira [14]2 years ago

5 0

X(m+n) = p
x = p/(m+n)

Hope this helps!

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And this one too please and thank u.

inn [45]

Answer:

$( - 4 \\ - 3$

Step-by-step explanation:

4unity to the left

3unity down

8 0

3 years ago

A soccer field is a rectangle 48 meters wide and 55 meters long. The coach asks players to run from one corner to the corner dia

Sindrei [870]

Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

The width of a rectangle = 55 m

We need to find the diagonal distance. We can use the Pythagoras theorem to find it.

$d^2=48^2+55^2\\\\d=\sqrt{5329}\\\\d=73\ m$

So, the required distance is equal to 73 m.

5 0

2 years ago

R=8cos3 theta graph plz graph it for me

insens350 [35]

Hope this help if you need help graphing I would use desmos

8 0

2 years ago

Sat question: a circle in the xy-plane has a diameter with endpoints (-1,-3) and (7,3). if the point (0,b) lies on the circle an

labwork [276]

1) use the distance formula to find that the radius (r) of the circle = 5

2) use the midpoint formula to find that the center of the circle (h,k) = (3, 0)

3) Now use the formula of a circle and input the (h,k) and r to create:

(x - 3)² + (y - 0)² = 5² → (x - 3)² + y² = 25

4) input the "x" value given in the question (x = 0) and solve for "y":

(0 - 3)² + y² = 25 → 9 + y² = 25 → y² = 16 → y = +/- 4

Since the question states that "b" must be positive, you can disregard the -4.

Answer: b = 4

4 0

2 years ago

Read 2 more answers

PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.

Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It is the slope of the line and $(x_ {0}, y_ {0})$ is a point through which the line passes.

We have the following equation of the slope-intersection form:

$y = 4x + 1$

Where the slope is $m = 4$

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

$m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}$

Thus, the equation will be of the form:

$y-y_ {0} = - \frac {1} {4} (x-x_ {0})$

Finally we substitute the given point and we have:

$y-3 = - \frac {1} {4} (x-6)$

Answer:

Option B

8 0

2 years ago