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Tanya [424]
3 years ago
14

Help me with geometry plzzzzzzzzzzzzzzzzzzzz

Mathematics
2 answers:
Svetach [21]3 years ago
8 0

Step-by-step explanation:

x+17+4x-34+6x+10=180(sum of angles in a triangle is 180)

11x-7=180

11x=187

x=187/11

x=17

Natalija [7]3 years ago
3 0

Answer:

x = 17

Step-by-step explanation:

A triangle's sum is 180 degrees, hence

6x + 10 + x + 17 + 4x - 34 = 180.

11x + 10 + 17 - 34 = 180

11x - 7 = 180

11x = 187

x = 17

hope this helps and is right!! p.s. i really need brainliest :)

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Select the two binomials that are factors of this trinomial. x^2-3x-28 help please I really bad need it
Fofino [41]

Answer:

(x-7)(x+4)

Step-by-step explanation:

To factor the equation, break it into two binomials which multiply to make the equation. To write these binomials (x+a)(x+b), find factors which multiply to -28 and add to -3 for a and b.

28: 1,2,4,7,14,28

-7+4 = -3

x^2-3x-28 = (x-7)(x+4)

8 0
3 years ago
Hurry please will mark brainliest!!!!!
Gnom [1K]

Answer:

C

Step-by-step explanation:

brianliest :3

4 0
3 years ago
Read 2 more answers
150+180 t856iebsoheheiwgfkehrhrh
Vikki [24]
330..............................
4 0
4 years ago
In ΔABC (m∠C = 90°), the points D and E are the points where the angle bisectors of ∠A and ∠B intersect respectively sides BC an
alexira [117]

Proof: \triangle CEH and \triangle CDG are isosceles triangles.

Explanation: Given in \triangle ABC D and E are angle bisector of   \angle Aand \angle B respectively.

Where G and H are points in AB such that DG\perp AB and EH\perp AB.

Let us take two triangles \triangle BCE and \triangle BEH

\angle BCE=\angle BHE (Right angles)

BE=BE, (common segment)

\angle HBE=\angle CBE ( Because BE is angle bisector)

Thus, \triangle BCE\cong\triangle BEH(ASA)

Therefore, EH= CE (CPCT)

So, in \triangle CEH, EH=CE ⇒\triangle CEH is an isosceles triangle.

Now, in \triangle ACD and \triangle ADG,

\angle ACD=\angle AGD (Right angles)

AD=AD (common segment)

\angle CAD=\angle DAG ( Because AD is angle bisector)

⇒\triangle ADC\cong\triangle AGD (ASA)

Thus, CD=DG (CPCT)

So, in \triangle CDG, CD=DG ⇒\triangle CDG is an isosceles triangle.


4 0
4 years ago
NEED ANSWER ASAP PLEASE!!
likoan [24]
(2x-3)+(3x+11)=6x-7
2x+3x-3+11=6x-7
5x-6x=-7+3-11
-x=-15
x=15
EG=6(15)-7=81

Hope this can help.
5 0
3 years ago
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