Answer:
Step-by-step explanation:
I am sorry but what is this suppose to be asking
Put it in the form
ax^2 + bx + c = 0
use the quadratic formula
x = [ -b + sqrt( b^2 - 4 ac ) ] / 2a
x = [ -b - sqrt( b^2 - 4 ac ) ] / 2a
7v^2 - 7v - 22 = 0
a = 7
b = -7
c = -22
v = [ 7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = 2.34
v = [ 7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = -1.34
Answer:
-189.8 J
Step-by-step explanation:
We are given that f
Force applied=F=35 Ni-37 Nj
Displacement, s=(-8.7m)i-(3.1m)j
We have to find the work done .
We know that
Work done=
Using the formula
Work done=
Work done=
Using 
Work done=-189.8J
Hence, the work done =-189.8 J
Answer:
No.
Step-by-step explanation:
Well, is the points (1, -9) does satisfy the equation y = 3x - 6. Then, substituting the values of x, and, y, into the equation y = 3x - 6, we should get a true equation.
y = 3x - 6
-9 = 3 * 1 - 6
-9 = 3 - 6
-9 = -3.
So, the points (1, -9) does not satisfy the equation y = 3x - 6.
Answer:

Step-by-step explanation:
Total amount paid for the nuts is $19.60
Total amount paid for the ribbons is $11.20
Profit made on each jar is 98¢= $0.98
Cost price of the nuts and ribbon for the 40 jars is 
Cost price for nuts and ribbonn for one jar = 
Selling price is the sum of the cost price and profit.
Selling price for one jar = 
They charged
for each jar.