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avanturin [10]
3 years ago
8

Help with this one!!! Show steps pls :)

Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

20 \times \frac{1}{8}

40

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Jenny has 220 ounces of cleaning solution that she wants to divide equally among 12 large containers how much cleaning solution
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Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len
Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

5 0
3 years ago
Which point is located at -0.135? <br> A<br> B <br> C or <br> D
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D as you can see on the number line d is 1/3 of the way to -2
6 0
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What is the Difference between 8 and -4
pav-90 [236]

Answer:

One is postive and the other is negative but both are integers and whole numbers

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How do I solve 3(x+5)=39
azamat
3(x+5)=39

3 * x + 3 * 5 = 39

3x + 15 = 39

3x = 39 - 15

3x= 24
x = 8


4 0
3 years ago
Read 2 more answers
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