$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)$

8 0

3 years ago

Jayde is wrapping a cube shape present that is 14 inches tall. How much wrapping paper will be needed to wrap the whole present?

gtnhenbr [62]

Answer:

1176in^2

Step-by-step explanation:

find the surface area of the cube

(14*14)6=1176 inches cubed

14*14 is finding the area of one side and then we multiply it by six because that's how many congruent sides there are

7 0

3 years ago

Read 2 more answers

1. Sam knows that his MP3 player has 40% of its battery life left and that the battery

Korolek [52]

Complete question :

Sam knows that his MP3 player has 40% of its battery life left and that the battery

charges by an additional 12 percentage points every 15 minutes. What percent of

the mp3's battery will be charged when Sam and his family leave? If mp3 was plugged in an hour before his family plan to leave.

Answer:

88%

Step-by-step explanation:

Time before leaving = 1hour

Current percentage = 40%

Charge rate = 12% every 15 minutes

Therefore,

Charge rate per minute :

12% / 15 = 0.8% per minute

Charge recieved after one hour (60 minutes) :

0.8% * 60

= 48%

Therefore, total charge after just before leaving is:

Current percentage + percentage received

40% + 48%

= 88%

6 0

2 years ago