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Ber [7]
3 years ago
9

Which of the following statement(S) are true of the discriminant?

Mathematics
2 answers:
Zarrin [17]3 years ago
8 0

SOS

Answer:

The answers are:

  1. The discriminant is b^2-4ac in the quadratic formula.
  2. The discriminant is the radicand of the quadratic formula.
  3. The discriminant is the value under the radical in the quadratic formula.

<em>Hope this helps!!</em>


lana [24]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:    A, C, D

Discussion:

The solution of the quadratic equation  ax^2 + bx + c = 0  is


x =        ( -b  +\-   (b^2 - 4ac) ^ (1/2) ) /2a


The expression b^2 - 4ac is called the discriminant, occurs in the numerator of the solution,  and also occurs inside a square root (called a radicand).

The question, while intelligible, should be stated more clearly.  

Regards, MrB

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I have nooo clue the problem doesn’t make sense
7 0
3 years ago
Can someone please help me with this problem?
Bumek [7]

Answer:

f'(1) = 2

Step-by-step explanation:

f(x) = 2x^2 -2x +3

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f'(x) = 2 * 2x - 2 * 1

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4 0
3 years ago
Rewrite the expression as an equivalent expression that does not contain powers of trigonometric functions greater than 1.
stich3 [128]
We are asked to express cos^ 3 x in terms of  powers of trigonometric functions not greater than 1

cos ^ 3 x is equal to cos x * cos^2 x. 
<span>cos^2 x = 1 - sin^2 x.
</span>sin^2 x  = (1 - cos 2x) /2 

the answer is cos ^ 3 x = cos x * (1 - <span> (1 - cos 2x) /2 )</span>




5 0
3 years ago
Please someone help me
Vanyuwa [196]
1.
1/4 is less then 2/4 or 1/2so if the denominator is equal it will be easier to multiply
3 0
3 years ago
Annabella wants to make the most economical decision so she chose the 3-year car loan so that after the loan is paid off to be a
Novay_Z [31]

Answer:

  • Annabella will save $4950.11 after 2 years.

Step-by-step explanation:

<h3>Given</h3>

  • Periodic payment P = $200,
  • Period t = 2 years,
  • Number of compounds, monthly n = 12,
  • Interest rate, r = 3.2% = 0.032.

<h3>To find</h3>

  • Future value of saving, F

<h3>Solution</h3>

Use periodic compound formula:

F=P\cfrac{(1+r/n)^{nt}-1}{r/n}

Substitute the values and calculate:

F=200\cfrac{(1+0.032/12)^{12*2}-1}{0.032/12} =4950.12     rounded

6 0
1 year ago
Read 2 more answers
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