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Sedaia [141]
3 years ago
8

For each babysitting job, Tamar charges $6 for bus fare plus $8 per hour. She only accepts babysitting jobs if the total charge

is at least $30. What is the minimum number of hours for a babysitting job she would accept?
A 2 and one-half hours
B 3 hours
C 4 hours
D 4 and one-half hours
Mathematics
2 answers:
gregori [183]3 years ago
8 0

Answer:

B. 3 hours

Step-by-step explanation:

It’s 6+8x=30

KengaRu [80]3 years ago
7 0

Answer:

B) 3 hours

Step-by-step explanation:

Hope this helped <333

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Where is the south of Asia​
yawa3891 [41]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

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Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
3 years ago
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