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Ede4ka [16]
3 years ago
10

PQR has vertices at P(2, 4), Q(3, 8) and R(5, 4). A similarity transformation maps PQR to ABC, whose vertices are A(2, 4), B(5.5

, 18), and C(12.5, 4). What is the scale factor of the dilation in the similarity transformation?
Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0
Use Pythagorean Theorem to calculate length of sides 

PQ = √(1^2 + 4^2) = √(17) 
QR = √(2^2 + 4^2) = √(20) 
RP = √(3^2 + 0^2) = √(9) 

AB = √(3.5^2 + 14^2) = √(208.25) 
BC = √(7^2 + 14^2) = √(245) 
CA = √(10.5^2 + 0^2) = √(110.25) 

A similarity transformation will maintain the relationship of sides: the smallest side of one triangle should correspond to the shortest side of the other triangle (and so on). 

Ratio of lengths (transformed/original) 

shortest with shortest 
CA/RP = √(110.25)/√(9) = 10.5/3 = 3.5 
middle 
AB/PQ = √(208.25)/√(17) = √(208.25/17) = √(12.25) = 3.5 
longest 
<span>BC/QR = √(245)/√(20) = √(12.25) = 3.5</span>
zhuklara [117]3 years ago
4 0

Answer:

3.5 is the correct answer just had question and it was correct

Step-by-step explanation:


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Given the following trigonometric ratio, enumerate the meaning ratio ​
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Answer:

The trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

\sin \theta = \frac{y}{h} (1)

Cosine

\cos \theta = \frac{x}{h} (2)

Tangent

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x} (3)

Cotangent

\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y} (4)

Secant

\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x} (5)

Cosecant

\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y} (6)

Where:

x - Adjacent leg.

y - Opposite leg.

h - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

h = \sqrt{x^{2}+y^{2}}

If y = AC and x = BC, then the trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

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mixer [17]
5y - 2x + 1 = 0.
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y = 2/5 x - 2/5

this tells us that tan(theta) = 2/5
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cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
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Step-by-step explanation:

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