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ikadub [295]
2 years ago
8

Place the indicated product in the proper location on the grid. (3 - c 2d )(4 - 4c 2d )

Mathematics
2 answers:
ivann1987 [24]2 years ago
8 0
The product of the expression given will be:
(3-c²d)(4-c²d)
expanding the expression we obtain
3(4-c²d)-c²d(4-c²d)
=12-3c²d-4c²d+c^4d²
simplifying the above we get:
c^4d²-7c²d+12

Answer: c^4d²-7c²d+12
Dmitrij [34]2 years ago
7 0

Answer:

12 - 16c^2d + 4c^4d

Step-by-step explanation:

(3 - c^2d)(4 - 4c^2d)

Distributive

12 - 12c^d - 4c^2d + 4c^4d^2

Combine like terms

12 - 16c^2d + 4c^4d^2

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Dagogo uploads 3 videos on his channel every month. Each video averages 15 minutes in length and gets an average of 150,000 new
Lana71 [14]

Answer: 20 months

Step-by-step explanation:

x months times y for views over 1 month = 9000000 views

3 x 150000(views per video) = 450000

9000000/450000= 20 months

4 0
2 years ago
Alan has forgotten his 4-digit PIN code.He knows it begins with a 6 and the 4 digits make an even number.How many different sets
Oxana [17]

Answer:

500.

Step-by-step explanation:

The last digit must end with 0, 2, 4, 6, 8   for the Pin code to be even.

The middle 2 digits may be any numbers.

So if the last number is 0 Then there are 10*10 = 100 possible PIN codes.

So  as there are 5 possible last digits , the total  possible sets of digits

= 5 * 100

= 500.

4 0
2 years ago
Match the expressions with the nonpermissible replacements for y
pantera1 [17]

<em>-7 _D_</em>

<em>\frac{3}{2} _A_</em>

<em>1 _C_</em>

<em>\frac{-1}{4} _B_</em>

<em>_A_ \frac{y^{2} -2y+1}{2y-3}</em>

<em>_B_ \frac{y(y+5)}{4y+1}</em>

<em>_C_ \frac{5y^{2}-6y+1 }{-5(y-1)}</em>

<em>_D_ \frac{y^{2}-y-6 }{-2(y+7)}</em>


3 0
3 years ago
Read 2 more answers
Three fourths a number plus 8 is 20 less than the number
VARVARA [1.3K]

Answer:

Equation:  \frac{3}{4}n+8=n-20

Solve for n:  n = 112

Step-by-step explanation:

To first set up the equation, you need to look at the verbal description and translate into numbers and operations:

'three fourths a number' =  \frac{3}{4} n

'plus 8' = + 8

'is' =

'20 less' = - 20

'the number' = n

Put the expressions together:

'three fourths a number plus 8':  \frac{3}{4}n+8

'20 less than the number': n - 20

Set them equal to each other and solve: \frac{3}{4}n+8=n-20

Add 20 to both sides: \frac{3}{4}n+8+20=n-20+20

Subtract \frac{3}{4}n from both sides: \frac{3}{4}n-\frac{3}{4}n+28=n-\frac{3}{4}n

Multiply both sides by \frac{4}{1}: \frac{4}{1}28=\frac{1}{4}n\frac{4}{1}

Solve for n:  n = 112

7 0
3 years ago
Please help! How do I solve this?
Advocard [28]
m\angle 6=m\angle3\\&#10;8x+7=6x+32\\&#10;2x=25\\&#10;x=12.5\\\\&#10;m\angle 6=8\cdot12.5+7=100+7=107\Rightarrow D&#10;
5 0
3 years ago
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