I REALLY NEED HELP WITH THIS

Mathematics

1 answer:

luda_lava [24]3 years ago

6 0

Answer:

x= 10

Step-by-step explanation:

Vertical angles theorem: 10x= 8x + 20

10x - 8x = 20 + 8x - 8x

2x = 20

x = 10

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Find the estimates of x^2-x-2=3

Julli [10]

Answer:

$x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79$

Step-by-step explanation:

Given

Quadratic equation is

$x^2-x-2=3\\x^2-x-5=0$

Roots of the quadratic equation $ax^2+bx+c=0$ are

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

So, for the given equation roots are

$x=\frac{1\pm\sqrt{(-1)^2-4(1)(-5)}}{2\cdot 1}\\x=\frac{1\pm\sqrt{21}}{2}\\so, x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79$

5 0

3 years ago

5. If W(-10, 4), X(-3,-1), and Y(-5, 11) classify AWXY by its sides. Show all work to justify your

Ierofanga [76]

Answer:

an isosceles right triangle

Step-by-step explanation:

The square of the length of a side can be found from the distance formula:

d^2 = (x2-x1)^2 +(y2-y1)^2

The square of the length of WX is ...

WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74

The square of the length of XY is ...

XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148

The square of the length of YW is ...

YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74

The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.