Angles formed by the segment $\overline{XZ}$ in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.

The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; 16 over 12 equals 12 over 9

Reasons:

The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;

Segment $\overline{XZ}$ is perpendicular to segment $\overline{WY}$

∠WZX and ∠XZY are right angles by definition of $\overline{XZ}$ perpendicular to $\overline{WY}$

∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)

$\displaystyle \frac{WZ}{XZ} = \frac{16}{12} = \mathbf{ \frac{4}{3}}$

$\displaystyle \mathbf{ \frac{XZ}{ZY}} = \frac{12}{9} = \frac{4}{3}$

Therefore;

$\displaystyle \frac{16}{12} = \frac{12}{9}$ , which gives, $\displaystyle \mathbf{\frac{WZ}{XZ} }= \frac{XZ}{ZY}$

Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and

that the included angles between the two sides, ∠WZX and ∠XZY are

congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-

Side, SAS, similarity postulate.

The option that best completes the proof is therefore;

$\displaystyle \frac{16}{12} = \frac{12}{9}$ which is; 16 over 12 equals 12 over 9

Learn more about the SAS similarity postulate here:

brainly.com/question/11923416

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2 years ago