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Ludmilka [50]
2 years ago
10

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
1 answer:
Vladimir [108]2 years ago
6 0

Answer:

B

Step-by-step explanation:

There is two wholes and one half.

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MATH EXPERTS I NEED YOU! Is it graph A, B, C, or D?
vichka [17]

Answer:

Its the first graph ok kid

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
7.2b + 6.5 > 4.8b – 8.1.
Marianna [84]
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
b
<
4.541
¯
6
b
<
Interval Notation:
(
−
∞
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4.541
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8 0
3 years ago
Jane estimates this product by computing 7 x 800.
nirvana33 [79]

Answer:

Bill is closer.

Step-by-step explanation:

Bill: 7 * 900 = 6,300

Jane:  7 * 800 = 5,600

Actual Answer: 7 * 876 = 6,132

5 0
3 years ago
Breoz
Viktor [21]

The second statement is:

B: a + b = b + a

Which is the commutative property, so we know that this statement is true.

<h3>Which statement is always true?</h3>

Remember that for integer numbers, we have the following properties:

  • Commutative property: A + B = B + A
  • Associative property: (A + B) + C = A + (B + C)

Now, in this case we know that a and b are integer numbers, first we can see that the second statement is:

B: a + b = b + a

Which is the commutative property, so we know that this statement is true.

The other 3 statements are false. You can see it by evaluating a = 0 and b = 1.

If you want to learn more about addition:

brainly.com/question/25421984

#SPJ1

6 0
1 year ago
HELP!!! I need help in simplifying this question.
kherson [118]

Answer: x^{-4}=\frac{1}{x^{4}}

Step-by-step explanation:

We have the following expression:

(\sqrt[3]{x^{2}} \sqrt[6]{x^{4}})^{-3}

Which can also be written as:

(x^{\frac{2}{3}} x^{\frac{4}{6}})^{-3}

Since we have exponents with the same base x inside the parenthesis, we can sum both exponents:

(x^{\frac{4}{3}})^{-3}

Now, we have to multiply the exponent out of the parenthesis with the inner exponent and have the following result:

x^{-4}=\frac{1}{x^{4}}

5 0
3 years ago
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