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beks73 [17]
2 years ago
11

CAN SOMEONE PLEASE HELP ME??

Mathematics
2 answers:
AVprozaik [17]2 years ago
6 0

Answer:

14

Step-by-step explanation:

We are given the area of the circle and the formula as well. My phone doesn't have thr pi logo, so I'm gonna just type pi.

Just work backwards and solve for the radius, r.

658 sq ft is the area of the circle. We need to solve for r and we have to divide by pi first on both sides just to have r left as the only variable.

658 = pi × r × r

658/pi = r × r

Once we get the r by itself, we have to take the square root since the r is squared in the formula.

Hope this helps!

Luba_88 [7]2 years ago
4 0

Answer:

Step-by-step explanation:

the answer is 14

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Can someone actually help and not tell me to use google. thanks.
solmaris [256]

Answer:

i deserved these

Step-by-step explanation:

3 0
3 years ago
Antonio ate 9/10 of a pizza on Monday. On Tuesday, he ate 3/10 of a pizza. How much pizza did Antonio eat on Monday and Tuesday?
AveGali [126]

He ate 1 1/5  (1.2) of pizza

6 0
2 years ago
What is the variance of the data set? 8, 9, 10, 16, 17
adoni [48]
Mean = (8 + 9 + 10 + 16 + 17) / 5 = 60/5 = 12.

x - mean:

8 - 12 = -4,  -4² = 16

<span>9 - 12 = -3,  -3² = 9
</span>
<span>10 - 12 = -2,  -2² = 4
</span>
<span>16- 12 = 4,  4² = 16</span>

<span>17- 12 = -5,  -5² = 25
</span>
Sum of the squares =   16 + 9 + 4 + 16 +25 = 70

Variance = 70/5 = 14

Variance = 14
6 0
2 years ago
If x varies directly as y, find x when y=8. x=11 when y=-3
andriy [413]

Answer:

x=-\frac{88}{3}

Step-by-step explanation:

When a quantity "A" varies DIRECTLY with another quantity "B", we can write the proportionality equation as:

A = kB

Where k is the proportionality constant (to be found)

In this problem, it is given x varies DIRECTLY with y, so we can write:

x = ky

Also, given, x = 11, y = -3, so we plug these into the equation and first find k:

x = ky

11 = k(-3)

k = -11/3

Now, we need to find x when y = 8, so we substitute and find x:

x=ky\\x=(-\frac{11}{3})(8)\\x=-\frac{88}{3}

8 0
3 years ago
What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!
ipn [44]

Answer:

x = 1 + \sqrt5, x = 1 - \sqrt5

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: ax^2 + bx + c = 0

Quadratic Formula: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

Given our Equation: g(x) = x^2 - 2x - 4

  • a = 1
  • b = -2
  • c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>
  • x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}
  • x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}
  • x = \frac{2\pm\sqrt{4 +16}}{2}
  • x = \frac{2\pm\sqrt{20}}{2}
  • x = \frac{2\pm\sqrt{4 * 5}}{2}
  • x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}
  • x = \frac{2\pm2\sqrt5}{2}
  • x = 1 + \sqrt5, x = 1 - \sqrt5
7 0
2 years ago
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