Given:
The x and y axis are tangent to a circle with radius 3 units.
To find:
The standard form of the circle.
Solution:
It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.
We know that the radius of the circle are perpendicular to the tangent at the point of tangency.
It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).
The standard form of a circle is:
Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting 
, we get
Therefore, the standard form of the given circle is .
Answer:
SAS Similarity
Step-by-step explanation:
ΔOPQ similar to ΔRST
∠Q = ∠T
OQ : RT = 28 : 84 = 1 : 3
QP : TS = 16 : 48 = 1 : 3
The measures of two sides of ΔOPQ are proportional to the measure of two side of ΔRST and their included angles are congruent. The triangles are similar by SAS Similarity.
Answer:
13.5
Step-by-step explanation:
6 + 3 = 9
9 × 3 = 27
27 ÷ 2 = 13.5
brainliest?
Answer:
omg its simple guys
Step-by-step explanation:
do the math.
Answer:
x = 8
Step-by-step explanation:
Angle J = Angle P, and Angle L = Angle L so the triangles have the same angle measures all the way around. Triangle JKL is the same as Triangle LMP, but smaller. it has been reduced by a ratio of 4:6. You then divide 4 by 6 to get the ratio in decimal form, and then multiply that by 12 to get the equivalent length for JK to PM
