X^2+2x^2-5x
((x^2)+2x^2)-5x
Pull the factors out
3x^2-5x=x(3x-5)
x(3x-5)
x(3x-5)*5x^2
5x(3x-5)*x^2
Final
5x^3*(3x-5)
13 its not hard aslo give n if not no one can figure it out
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Group 1:
μ1 = 59.7
s1 = 2.8
n1 = sample size = 12
Group 2:
μ2 = 64.7
s2 = 8.3
n2 = sample size = 15
α = 0.1
Assume normal distribution and equ sample variance
A.)
Null and alternative hypothesis
Null : μ1 = μ2
Alternative : μ1 < μ2
B.)
USing the t test
Test statistic :
t = (m1 - m2) / S(√1/n1 + 1/n2)
S = √(((n1 - 1)s²1 + (n2 - 1)s²2) / (n1 + n2 - 2))
S = √(((12 - 1)2.8^2 + (15 - 1)8.3^2) / (12 + 15 - 2))
S = 6.4829005
t = (59.7 - 64.7) / 6.4829005(√1/12 + 1/15)
t = - 5 / 2.5108165
tstat = −1.991384
Decision rule :
If tstat < - tα, (n1+n2-2) ; reject the Null
tstat < t0.1,25
From t table :
-t0.1, 25 = - 1.3163
tstat = - 1.9913
-1.9913 < - 1.3163 ; Hence reject the Null
Answer:
787.50
Step-by-step explanation:
interest=principle*rate*time/100
interest=3500*7.5*3/100
interest=35*7.5*3
interest=787.50
1) 6/15 or 2/5
2) .4 or 40%
for the table its gonna be 14/32 or 7/16
then 5/17 then 11/25 then 8/29 then 3/14
then 9/31 then 12/32 or 3/8 then 8/30 or 4/15 then 2/19 then 15/32
