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2 years ago

What is the slope of the line if one point is (-2,1) and (1,4)

Mathematics

1 answer:

tiny-mole [99]2 years ago

8 0

The answer is the slope m=1

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Can you help me for real thank you a bunch

Mama L [17]

Answer:

Ok so the original bill you full out is $32.00 in that box. and the next box put 15% of $32

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2 years ago

Are loops considered directed edges in terms of a digraph

Leya [2.2K]

Yes if you would like them to be considered that way depending on you x axis degree

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3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

3 years ago

1/5 plus 3/10 in the most simple form

Reptile [31]

Hey there!

1/5 + 3/10
= 2/10 + 3/10

= 2 + 3/10 - 0

= 5/10

= 5 ÷ 5 / 10 ÷ 5

= 1 / 2

Therefore, your answer is: 1/2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

6 0

2 years ago

What are the measures of each interior and exterior angles of regular quadrilateral MNOP?

stiks02 [169]

Answer:

A regular polygon is a polygon that is equilateral and equiangular.

The only regular quadrilateral is the square.

We know that all the interior angles of a square are 90° each, so we are fine with that.

Now, for the exterior angles.

If we fix our position in the vertex, we can do from one side, to the same side, a full rotation of 360°.

Now, if we only do an external rotation, this means, from one side to other side, we will do a rotation of 360° minus the interior angle:

this is:

360° - 90° = 270°

Below is an image as a guide of this.

8 0

3 years ago