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givi [52]
3 years ago
9

How do I resolve this? Como resuelvo esto?

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ -----\\ A=144\pi  \end{cases}\implies 144\pi =\pi r^2\implies \cfrac{144\pi }{\pi }=r^2 \\\\\\ 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r} \\\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi \boxed{12}\implies C=24\pi

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Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
2 years ago
WHO CAN HELP ME WITH THIS QUESTION PLEASE PLEASE PLEASE
natima [27]

Answer:

105.12

Step-by-step explanation:

6 0
3 years ago
Sonny run 4.5 km everyday. One day after he ran 2.5 km, he felt very sick. He walked 0.3 meters before a friend gave him a ride
MAXImum [283]

2 km

4.5km - 2.5km = 2km. The 0.3m is negligible unless it means kilometers. If it is indeed kilometers, it is 1.7km.

6 0
2 years ago
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10 hundredths in standard form.
Aneli [31]
.10 I hope that that helps you :)
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2 years ago
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Do the segment lengths 9,12 and 15 from a right triangle
sweet [91]
Yes. Use pythagorean theorem to find that: 9^2 + 12^2 =225 and 15^2 =225.
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