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givi [52]
3 years ago
9

How do I resolve this? Como resuelvo esto?

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ -----\\ A=144\pi  \end{cases}\implies 144\pi =\pi r^2\implies \cfrac{144\pi }{\pi }=r^2 \\\\\\ 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r} \\\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi \boxed{12}\implies C=24\pi

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