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Arada [10]
3 years ago
11

PLEASE HELP QUICK WILL MARK BRAINLIEST.

Mathematics
1 answer:
ioda3 years ago
5 0

Answer:

4.57

Step-by-step explanation:

7 can go into 32 4 times but your remainder is going to be 5

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A dining room is 21 ft long. On a blueprint, the dining room is 3.5 ft long and 2.5 ft wide. The actual width of the dining room
mars1129 [50]

Answer:

15 ft.

Step-by-step explanation:

the ratio of the real room to the blueprint is 21/3.5, which simplifies to 6.

You have to multiply 6 by 2.5 to get 15

4 0
2 years ago
Help me solve this :( I have a test tomorrow plz
goldfiish [28.3K]
Mean is 11.5 Median is 10 and Range is 12 and Outlier is 19
5 0
3 years ago
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A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2
AVprozaik [17]
Area of the rectangular mat = 12 x 4 = 48 in²

Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²

P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)

Answer: The probability of landing in one of the circles is 0.79.
7 0
3 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
carly wants to ride the bumper cards 5 times and the ferris wheel 2 times. it cost 5 tickets to ride the bumper cars and 5 ticke
Blababa [14]
25 to ride the bumper cars 
10 to ride the Ferris wheel 
35 tickets total
3 0
3 years ago
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