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3 years ago

What information do you need to write the equation of a transformed quadratic equation in vertex form

Mathematics

1 answer:

Mrac [35]3 years ago

6 0

Answer:

To convert a quadratic from y = ax2 + bx + c form to vertex form, y = a(x - h)2+ k, you use the process of completing the square.

Step-by-step explanation:

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What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?

nika2105 [10]

The slope-point form:

$y-y_1=m(x-x_1)$

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (7, -8) and (-4, 6). Substitute:

$m=\dfrac{6-(-8)}{-4-7}=\dfrac{14}{-11}=-\dfrac{14}{11}\\\\y-6=-\dfrac{14}{11}(x-(-4))\\\\\boxed{y-6=-\dfrac{14}{11}(x+4)}$

7 0

3 years ago

X/-3-50=0 PLEASE HELP

Pachacha [2.7K]

Hello!

First of all, let's add 50 to both sides.

x/-3=50

Now we multiply both sides by -3.

x= -150

I hope this helps!

3 0

3 years ago

16x⁴-4x²-4x-1 and 8x³-1<br>HCF

IgorLugansk [536]

Answer:

We have expanded formula of (-4x-1)² = a²+2ab+b².

So, we write the formula in square form as (a+b)².

Since we have a²-b² in step 4. We further write this as (a+b)(a-b). This is the factor formula of a²-b².

As we had two terms in place of in (a+b)(a-b), we multiply the term 'b' with '+' and '-' sign respectively.

Write the second expression given in the question.

Write the terms in the form of cube.

Write the factor formula of a³-b³) in the form of (a-b)(a²+ab+b²).

Write the H.C.F. (Highest Common Factor) of the given expressions by analysing the factors you generated in each expressions. Here, (4x²+2x+1) are the common factors.

4 0

2 years ago

What is the function of the chloroplasts in an animal cell

11111nata11111 [884]

There are no chloroplasts in animal cells

Chloroplasts are organelles that photosynthesize glucose(energy) found in plant cells and some algae

7 0

3 years ago

A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were

quester [9]

Answer:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

Step-by-step explanation:

For this case we have the following distribution given:

X 1 2 7

P(X) 1/5 2/5 2/5

We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

7 0

3 years ago