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2 years ago

What is the slope of the line?

Mathematics

2 answers:

Naddik [55]2 years ago

8 0

The slope would be B) -1/2

Because it is going down by one unit and 2 to the right

zvonat [6]2 years ago

4 0

Your answer is B) -1/2

One way of finding this answer is by using the slope equation (y2 - y1)/(x2 - x1) and substituting in the coordinates on the line. This gets you

(2 - 3)/(4 - 2) = -1/2

Another way is to find the slope by looking at the graph, and seeing that it must be negative because it slopes downwards to the right instead of up, and that it must be 1/2 because for every 1 unit you go down, you go 2 across, which means your y/x is 1/2.

I hope this helps! Let me know if you have any questions :)

You might be interested in

Pls help me on this.......

Ganezh [65]

Hey there!

Your answer is $-4x+7$

Here are the steps to solve:

Given:

$-5x-(x-7)$

Distribute negative sign:

$-5x+x+7$

Add like terms:

$-4x+7$

Have a great day! Hope it helped!

7 0

2 years ago

P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)$

$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm \sqrt{4+16}}{2}=\frac{2\pm \sqrt{20}}{2}=\frac{2\pm 2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}$

7 0

2 years ago

Find the selling price of a $36 item after a 50% markup

agasfer [191]

Answer:

$54

Step-by-step explanation:

36 divided by 2= 18

$36+$18=$54

7 0

1 year ago

14 less than a number all divided by the same number

Fynjy0 [20]

Answer:

(n-14) / n

Step-by-step explanation:

n is your number;

"14 less" means "subtract 14", --> we have (n-14);

now we need to divide (n-14) by same number as your number, which is "n"---> final expression is: (n-14)/n

6 0

3 years ago

Lines g, h, and I are parallel and m < 2 =129

vampirchik [111]

Answer:

All angles in this diagram are 51 or 129. See below for a specific angle.

Step-by-step explanation:

Parallel lines cut by a transversal have specific angle relationships.

Alternate Interior Angles are angles across the transversal between pairs of parallel lines. These angles are congruent. Example: 3, 6, 7, and 10 are all congruent and are pairs of alternate interior angles. 4, 5, 8, and 9 are congruent as well.
Alternate Exterior Angles are angles across the transversal outside of the parallel lines. These angles are congruent. Example 2 & 11 are congruent alternate exterior angles. 1 and 12 are another set.
Supplementary angles are angles which form a line and add to 180. If angle 1 + angle 2 = 180 and angle 2 = 129, then Angle 1+ 129 =180. Angle 1 must be 51 degrees.
Vertical angles are angles across a vertex. They are congruent. Example: Angle 2 and Angle 3 are both 129.

Using these relationships, the following angles have the following measures:

Angle 1 = 51

Angle 2 = 129

Angle 3 = 129

Angle 4 = 51

Angle 5 =51

Angle 6 = 129

Angle 7 = 129

Angle 8 = 51

Angle 9 = 51

Angle 10 = 129

Angle 11 = 129

Angle 12 = 51

3 0

2 years ago