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3 years ago

Need help with this math problem

Mathematics

1 answer:

faltersainse [42]3 years ago

6 0

Answer:

choice 2) x+2y+3 = 7

Step-by-step explanation:

equation to match:

x+2y = 4

add 3 to each side

x+2y+3 = 7 (which is the same as choice 2, x+2y+3 = 7)

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What is the measure of arc bc?<br> A. 76<br> B. 40<br> C. 96<br> D. 58

Veseljchak [2.6K]

Answer:

A. 76

Step-by-step explanation:

Angle A is half the difference between the measures of arc DE and BC.

m∠A = (1/2)(DE -BC)

20 = (1/2)(116 -BC) . . . . substitute the given values

40 = 116 -BC . . . . . . . . multiply by 2

BC = 116 -40 . . . . . . . . add BC -40

BC = 76

_____

<em>Comment on intersecting secants</em>

When the secants intersect <em>inside</em> the circle, the angle where they cross is half the <em>sum</em> of the intercepted arcs. When they intersect <em>outside</em> the circle (as here), the angle where they meet is half the <em>difference</em> of the intercepted acs.

Sometimes it is easier to remember two related relationships than it is to remember just one of them.

4 0

3 years ago

PLEASE HELP...SUPER URGENT!!!!...50 POINTS!!!!...WILL GIVE BRAINLIEST!!!

wlad13 [49]

X= 3 to x = 4 has a greater rate of change

4 0

3 years ago

Read 2 more answers

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*

pickupchik [31]

<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation $x^4-41x^2=-400$ .

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

$x^4-41x^2+400=-400+400$ .

$x^4-41x^2+400=0$ .

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

$x^4-25x^2-16x^2+400=0$

Making it into two groups, we get

$(x^4-25x^2)+(-16x^2+400)=0$

Factoring out GCF of each group, we get

$x^2(x^2-25)-16(x^2-25)=0$

$(x^2-25)(x^2-16) =0$

Factoring out $(x^2-25)$ and $(x^2-16)$ separately by difference of the squares identity $a^2-b^2=(a-b)(a+b)$ , we get

$(x^2-25) = x^2-5^2= (x-5)(x+5)$ and

$x^2-16 = x^2-4^2 =(x-4)(x+4)$ .

Therefore,

$(x-5)(x+5)(x-4)(x+4) =0$

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

6 0

3 years ago

Help me? Can't figure it out

Simora [160]

Pi = 3. Area of a circle = pi×r squared.

R is radius, and the radius of that circle is 11 m. therefore, 3.14×11 squared will give you your answer. Don't forget, exponent before multiplication

11^2 = 121
121×3 = 363 That's the area of the big circle.

Now, 11÷2 gives you the radius of the small circles. you get 4.5
4.5^2 = 20.25
20.25*3 = 60.75

That's the area of ONE small circle. double it and you have the area of 2.

60.75×2= 121.5

Now just subtract the area of the small ones from the area of the big one to find the area of the shaded region.

363-121.5= 241.5

Now, you're done!

5 0

3 years ago

A total of about 230 million turkeys were raised in the U.S. last year. Were more than one-quarter of them raised in Minesota if

pochemuha

No, 17.39% were raised in Minnesota.

You can find this by dividing 40,000,000 by 230,000,000 and then converting to a percent by multiplying by 100.

40,000,000/230,000,000=.1739
.1739 x 100= 17.39%

8 0

3 years ago

Need help with this math problem​

Need help with this math problem