Question

If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x)

Answer 1

Answer:

$4(x-7)^2-(x-7)+3$

Step-by-step explanation:

Given the functions:

$s(x)=x-7$ and $t(x)=4x^2-x+3$

We have to find the $(t \circ s)(x)$

$(t \circ s)(x) = t(s(x))$

Substitute the function s(x) we have;

⇒$t(s(x)) = t(x-7)$

Replace x with x-7 in t(x) we have;

⇒$t(x-7) = 4(x-7)^2-(x-7)+3$

⇒$(t \circ s)(x) = 4(x-7)^2-(x-7)+3$

Therefore, the expression which is equivalent to $(t \circ s)(x)$ is:

$4(x-7)^2-(x-7)+3$

Answer 2

(t o s)(x) = t(s(x)) 
s(x) = x - 7 
t(x - 7) = 4(x-7)^2 - (x - 7) + 3