1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blizzard [7]
3 years ago
15

A manufacturer of matches randomly and independently puts 22 matches in each box of matches produced. The company knows that one

-tenth of 5 percent of the matches are flawed. What is the probability that a matchbox will have one or fewer matches with a flaw?
Mathematics
1 answer:
tangare [24]3 years ago
6 0

Answer:

The probability that a matchbox will have one or fewer matches with a flaw is 0.9946 approximately.    

Step-by-step explanation:

Consider the provided information.

A manufacturer of matches randomly and independently puts 22 matches in each box of matches produced. The company knows that one-tenth of 5 percent of the matches are flawed.

One-tenth of 5 percent can be written as 0.5%

Here we have the value of n=22 and the value of p=0.5%=0.005

We want the probability that a matchbox will have one or fewer matches with a flaw.

That means P(X\leq 1)=P(X=0)+P(X=1)

Thus the required probability is:

P(X\leq 1)=\binom{22}{0}0.005^0(1-0.005)^{22}+\binom{22}{1}0.005^1(1-0.005)^{21}\\P(X\leq 1)=(0.995)^{22}+\binom{22}{1}0.005^1(0.995)^{21}\\P(X\leq 1)\approx 0.8956+22\times 0.005\times (0.995)^{21}\\P(X\leq 1)=0.8956+0.099\\P(X\leq 1)=0.9946

Hence, the probability that a matchbox will have one or fewer matches with a flaw is 0.9946 approximately.

You might be interested in
3(5+3)^2 +14<br><br><br> help me pls i cannot deal w my parents again
Scilla [17]

Answer:

206

Step-by-step explanation:

I put it in a calculator

6 0
3 years ago
Read 2 more answers
Help plz ahhh plz pretty plz
Flauer [41]

Answer: 158 as area and perimeter 62

Step-by-step explanation:

4 0
3 years ago
Which equations are in standard form? Check all that apply
professor190 [17]

Answer:

2x + 3y = -6

-4x + 3y = 12

5x + 3y = }

x - y = 5

Step-by-step explanation:

Standard Form is  Ax+By=C.  

2x + 3y = -6, -4x +3y = 12, 5x + 3y = '?', and x - y = 5 are the equations that are in standard form.  

'2x+3 = 6' does not have the 'y' to make it standard form.

'y = 2x + 5' is slope-intercept form.

5 0
3 years ago
HELLPP PLEASE OMGG I WILL GIVE YOU ALL MY POINTSS​
weeeeeb [17]

Answer:

I believe it is $60

Step-by-step explanation:

She had $10. Her mom gave her $30 more. Her dad had given her $30.Her aunt and uncle gave her $100 more. She had another $20. It gives you the hints in the text.

Hope this helps!

6 0
2 years ago
Read 2 more answers
If (44)x = 432, what is the value of x?
Gemiola [76]

Answer:

x= 9.81... repeating

Step-by-step explanation:

Divide 44 to isolate x.

(44)x = 432

x= 432/44

x= 9.818

Or if you want a fraction,

x= 108/11

8 0
2 years ago
Read 2 more answers
Other questions:
  • Which of the following functions has a graph in which the vertex and axis of symmetry are to the left of the vertex and axis of
    15·1 answer
  • Please help me with this​
    15·2 answers
  • Which of the following is the the correct factorization of this trinomial.
    8·2 answers
  • Is 1044 2 3 5 6 9 10
    6·1 answer
  • 15(y - 4) - 2 (y - 2 )= - 5 (y+ 6)<br><br> pls solve fast<br> step by step
    9·2 answers
  • A student concluded that the solution to the
    9·1 answer
  • Write the equation of the line that has a slope of -3/2 and passes through (4, -3)
    15·1 answer
  • The sum of outer angles of a polygon is twice the sum of inner angles. How many sides does it have?
    13·2 answers
  • On a coordinate plane, a right triangle has points A (negative 5, negative 6), B (negative 5, negative 2), C (negative 2, negati
    9·1 answer
  • Compute the monthly payments for the add on interest loan. The amount of the loan is $8,276.17. The annual interest rate is 5.7%
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!