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mrs_skeptik [129]
3 years ago
13

Determine whether the data described are qualitative or quantitative. The maximum speed limit on interstate highways.

Mathematics
1 answer:
dalvyx [7]3 years ago
6 0
The answer is B: Quantitative
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On april 1 of the current year, a company purchased and placed in service a machine with a cost of $240,000. the company estimat
Viktor [21]

The answers to the questions are:

  • a. $33,750
  • b. $36000
  • c. $90000

a. <u>the straight-line method of depreciation</u>

\frac{cost of machine - salvage}{useful life} * period

= (240000 - 60000) / 4 * (9 / 12)

= $33,750

The debit is 33750 as well as the credit

b. <u> the units-of-production method of depreciation</u>

(240000 - 60000) / 60000 * 12000

= $36000

c. <u>the double-declining balance method of depreciation</u>

(24000 *2 /4) * (9/12)

= $90000

Read more on depreciation here: brainly.com/question/1203926

#SPJ1

8 0
2 years ago
Quotient of 213.21 and 15.8. rounded to nearest tenth
lesya692 [45]
Quotient = 213.21 ÷ 15.8 ≈ 13.494

≈ 13.5 to the nearest tenth.
8 0
3 years ago
Read 2 more answers
Bob did chores for his neighbor. The first day he earned $8. Then he earned $10 a day for
Bumek [7]

Answer: $128

Step-by-step explanation: So first Bob earned 8 dollars. Then he started earning 10 dollars a day every week for 2 weeks. that would have been 148 dollars (plus the 8 dollars he earned in the beginning), but he took a break once a week, subtracting 20 dollars from his pay, giving him 128 dollars in total.

Let me know if this was helpful! :D

3 0
4 years ago
Find the slope of the line that passes through: (6, 16) and (2, -4).
ratelena [41]

Answer:

5

Step-by-step explanation:

Slope formula=

\frac{y2-x2}{y1-x1}

so the slope is

\frac{-4-16}{2-6}

or

\frac{-20}{-4}

or5

so the slope is 5

Hope this helps ;D

6 0
3 years ago
the sum of the first twelve terms of arithmetic progression [AP] is 168. if the third term is 7. find the value of the common di
34kurt

Answer:

Common difference = 2

First term = 3.

Step-by-step explanation:

3rd term = a1 + (3 - 1)d  = 7    where a1 = first term and d = the common difference.

Sum of the first 12 terms = (12/2)[2a1 + (12-1)d] = 168

so 6(2a1 + 11d) = 168

So simplifying, we have the following system:

 a1 + 2d = 7  ..................(A)

12a1 + 66d = 168

2a1 + 11d = 28.................(B)   Multiplying equation A by - 2:

-2a1 - 4d =- -14                      Adding this to equation B

7d = 14

d = 2

Now plug this into equation A:

a1 + 2(2) = 7

a1 = 7-4

a1 = 3.

3 0
4 years ago
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