3 years ago

I need help (10) pts

Mathematics

2 answers:

Margaret [11]3 years ago

5 0

Answer:

-43+(-28)= -43-28

=> -71

Hope this helps you mate ♪＼(*＾▽＾*)／＼(*＾▽＾*)／♪☆＼(^０^＼) ♪(／^-^)／☆♪☆＼(^０^＼) ♪(／^-^)／☆♪☆＼(^０^＼) ♪(／^-^)／☆

miv72 [106K]3 years ago

3 0

Answer:

-71

Step-by-step explanation:

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3 years ago

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sp2606 [1]

$\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}$

Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

Prologarithmize both parts of the equation:

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

Divide both parts of the equation by 2:

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

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1 year ago