Answer:
The probability that the sample proportion exceeds 0.16 is 0.2061.
Step-by-step explanation:
We are given that according to a 2009 Reader's Digest article, people throw away approximately 13% of what they buy at the grocery store.
You plan to randomly survey 101 grocery shoppers to investigate their behavior.
Let = sample proportion
The z-score probability distribution for the sample proportion is given by;
Z = ~ N(0,1)
where, = sample population = 0.16
n = sample of grocery shoppers = 101
Now, the probability that the sample proportion exceeds 0.16 is given by = P( > 0.16)
P( > 0.16) = P(
>
) = P(Z > 0.82) = 1 - P(Z
0.82)
= 1 - 0.7939 = <u>0.2061</u>
The above probability is calculated by looking at the value of x = 0.82 in the z table which has an area of 0.7939.