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luda_lava [24]
3 years ago
11

Please answer the question below.

Mathematics
2 answers:
zlopas [31]3 years ago
7 0
The answer to your question I’m pretty sure would be the section option 4:2
hammer [34]3 years ago
5 0
The answer to the question is B (the second option 4:2)
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Evaluate expression when a=6 a2-6a+4
Mekhanik [1.2K]
The first step to solving this problem is to plug in 6 where you see a in the expression
-6² - 6 (-6) + 4
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-36 + 36 + 4
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vagabundo [1.1K]

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Solve using the quadratic formula: 2n^2= 6n - 2
bekas [8.4K]

Answer:

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n=(-b \pm \sqrt{b^2-4ac} )/2a\\\\n=(-(-6) \pm \sqrt{(-6)^2-4(2)(2)} )/2(2)\\\\n=(6 \pm \sqrt{36-16} )/4\\\\n=(6 \pm \sqrt{20} )/4\\\\n=(6 \pm 2\sqrt{5} )/4\\\\n=(3 \pm 1\sqrt{5} )/2\\\\n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

3 0
3 years ago
Plzz plzzz explain this!!!!
Shalnov [3]
Do you need for both or just one?
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number 3 going across the x axis

number 5 going across the y axis

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3 years ago
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