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Fed [463]
3 years ago
6

A rectangle is a four sided flat shape where every integer angle is a right angle. Therefore, opposite sides are parallel and co

nsecutive sides are perpendicular. Rae is drawing rectangle PQRS on a coordinate plane. The rectangle has coordinates P (-1,2), Q(2,4), R(x,y) and S(3,-4)

Mathematics
1 answer:
snow_lady [41]3 years ago
7 0

we know that

The rectangle has coordinates P (-1,2), Q(2,4), R(x,y) and S(3,-4)

using a graph tool

see the attached figure

Step 1

<u>Find the slope of the line PS</u>

the slope is equal to

m=(y2-y1)/(x2-x1)

mPS=(-4-2)/(3+1)=-6/4=-3/2

Step 2

<u>Find the equation of the line QR</u>

we know that

PS and QR are parallel lines

so

their slopes are the same

mQR=-3/2

with mQR and the point Q(2,4) find the equation of the line

y-y1=m*(x-x1)

y-4=(-3/2)*(x-2)

y=(-3/2)*x+3+4--------> y=7-(3/2)*x

Step 3

<u>Find the equation of the line SR</u>

we know that

SR and QR are perpendicular lines

so

the product of their slopes is equal to minus one

mSR*mQR=-1

mSR=2/3

with mSR and the point S(3,-4) find the equation of the line SR

y-y1=m*(x-x1)

y+4=(2/3)*(x-3)

y=(2/3)*x-2-4---------> y=-6+(2/3)*x

Step 4

Find the intersection of the lines QR and SR

we know that

the intersection of the lines QR and SR is the point R

y=7-(3/2)*x------> equation 1

y=-6+(2/3)*x------> equation 2

equate equation 1 and equation 2

7-(3/2)*x=-6+(2/3)*x

7+6=(2/3)*x+(3/2)*x

13=(2/3)*x+(3/2)*x

Multiply by 6 both sides

6*13=4*x+9*x

13*x=6*13

x=6

find the value of y

y=-6+(2/3)*x------> y=-6+(2/3)*6---------> y=-6+4

y=-2

therefore

<u>the answer is</u>

The coordinates of point R are (6,-2)

see the attached figure N 2

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Which of the following is not equal to the other values? cos31.7° cos211.7° cos328.3° cos(-391.7°)
luda_lava [24]

Answer:

* cos 211.7 not equal the other values

Step-by-step explanation:

* Lets revise the angles in the four quadrant

- If the angle in the first quadrant is Ф, then the equivalent angles to

 it in the other three quadrant are

# 180° - Ф ⇒ 2nd quadrant (sin only +ve)

# 180° + Ф ⇒ 3rd quadrant (tan only +ve)

# 360° - Ф ⇒ 4th quadrant (cos only +ve)

# -Ф ⇒ 4th quadrant (cos only +ve)

# -180 + Ф ⇒ 3rd quadrant (tan only +ve)

# -180 - Ф ⇒ 2nd quadrant (sin only +ve)

# -360 + Ф ⇒ 1st quadrant (all are +ve)

* Lets solve the problem

∵ Ф = 31.7°

∵ cos 31.7 = +ve value

∵ 180° + Ф° = 180° + 31.7° = 211.7°

∵ cos (180° + Ф°) = - cos Ф° ⇒ cos (180° + Ф°) in the 3rd quadrant is

  same value as cos Ф but with -ve sign

∴ cos 211.7° = - cos 31.7°

∴ cos 31.7° ≠ cos 211.7°

∵ 360° - Ф° = 360° - 31.7° = 328.3°

∵ cos (360° - Ф°) = cos Ф° ⇒ cos (360° - Ф°) in the 4th quadrant has the

  same value and sign with cos Ф°

∴ cos 328.3° = cos 31.7°

∴ cos 31.7° = cos 328.3°

∵ -391.7° + 360° = -31.7° ⇒ more then clockwise turn by 31.7°

∵ cos (-Ф°) = cos Ф° ⇒ cos (-Ф°) in the 4th quadrant has the same value

  and sign with cos Ф°

∴ cos (-31.7°) = cos 31.7°

∴ cos 31.7° = cos (-390.7°)

* cos 211.7 not equal the other values

6 0
3 years ago
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